Positive even-odd effects in the maximal kinetic energy and negative even-odd effects in the minimal excitation energy of fragments from thermal neutron induced fission of 235U

Abstract Based on the Coulomb effect hypothesis it is shown that positive even-odd effects of the maximal total kinetic energy (K max) and negative even-odd effects of the total minimal excitation energy (X max), as a function of charge (Z) and neutron number (A) of fragments, respectively, are not in contradiction. According to the Coulomb effect hypothesis, K max is equal to the maximal Coulomb interaction energy (C max) reached by the most compact scission configuration. The fragmentation corresponding to Z = 41 and A = 103 is an exceptional case for which scission configuration is formed by complementary fragments in their corresponding ground states. However, more symmetrical o more asymmetrical fragmentations than that need to be out of their ground states, which implies that K max = C max < Q.

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Bibliographic Details
Main Authors: Montoya,M., Collin,V.
Format: Digital revista
Language:English
Published: Sociedad Mexicana de Física 2017
Online Access:http://www.scielo.org.mx/scielo.php?script=sci_arttext&pid=S0035-001X2017000200151
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Summary:Abstract Based on the Coulomb effect hypothesis it is shown that positive even-odd effects of the maximal total kinetic energy (K max) and negative even-odd effects of the total minimal excitation energy (X max), as a function of charge (Z) and neutron number (A) of fragments, respectively, are not in contradiction. According to the Coulomb effect hypothesis, K max is equal to the maximal Coulomb interaction energy (C max) reached by the most compact scission configuration. The fragmentation corresponding to Z = 41 and A = 103 is an exceptional case for which scission configuration is formed by complementary fragments in their corresponding ground states. However, more symmetrical o more asymmetrical fragmentations than that need to be out of their ground states, which implies that K max = C max < Q.